IXL | Divide by 2-digit numbers using partial quotients | 5th grade math

or

Use the partial quotients method to find

336

÷

26

.

Fill in the missing numbers.

R

2

6

3

3

6

2

6

0

–

×

2

6

5

2

–

×

2

6

ref_doc_title.

or

Learn with an example

question

Use the partial quotients method to find

697

÷

25

.

Fill in the missing numbers.

R

2

5

6

9

7

2

5

0

–

×

2

5

2

5

0

–

×

2

5

1

7

5

–

×

2

5

solution

Find

697

÷

25

using the partial quotients method. Subtract multiples of 25 from the dividend until the remaining number is less than 25.

The first multiple is 250, which is equal to

10

×

25

.

Subtract 250 from 697.

2

5

6

9

7

2

5

0

–

1

0

×

2

5

4

4

7

The next multiple is also 250. Subtract 250 from 447.

2

5

6

9

7

2

5

0

–

1

0

×

2

5

4

4

7

2

5

0

–

1

0

×

2

5

1

9

7

The last multiple is 175, which is equal to

7

×

25

.

Subtract 175 from 197.

2

5

6

9

7

2

5

0

–

1

0

×

2

5

4

4

7

2

5

0

–

1

0

×

2

5

1

9

7

1

7

5

–

7

×

2

5

2

2

25 goes into 697 a total of

10

+

10

+

7

=

27

times. The quotient is 27.

2

7

2

5

6

9

7

2

5

0

–

1

0

×

2

5

4

4

7

2

5

0

–

1

0

×

2

5

1

9

7

1

7

5

–

7

×

2

5

2

2

The remainder is the last difference, 22.

2

7

R

2

2

2

5

6

9

7

2

5

0

–

1

0

×

2

5

4

4

7

2

5

0

–

1

0

×

2

5

1

9

7

1

7

5

–

7

×

2

5

2

2

Looking for more? Try these:

Lesson: Partial quotients

or

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Teacher tools

Work it out

Not feeling ready yet? These can help:

G.1Divisibility rules

E.6Divide multi-digit numbers by 1-digit numbers

K.12Divide using partial quotients

Lesson: Partial quotients